288 packets of biscuit,each having 12 biscuits, are packed in 9 cartoons. How many such cartoons are required to pack 1920 biscuits
Answers
Answered by
34
288 packet each have contain 12
Then 288×12= 3456 biscuit
3456 biscuit packet in 9 carton
Then each carton contain 3456/9 =384 biscuit
Then 1920 biscuit need for packet
1920/384= 5
5 carton required.
Then 288×12= 3456 biscuit
3456 biscuit packet in 9 carton
Then each carton contain 3456/9 =384 biscuit
Then 1920 biscuit need for packet
1920/384= 5
5 carton required.
budhianahak1998:
Welcome
Answered by
22
Dear friend,
No. of packets = 288
No. of biscuits 1 packet contains = 12 biscuits
Total no. of biscuits = 3456
No. of cartons = 9
Then,
Cartons for 3456 biscuits = 9
Cartons for 1 biscuit = 9/3456
Cartons for 1920 biscuits = (9/3456) × 1920
= 5
Answer. 5 cartons are needed.
Hope it helps !!!
No. of packets = 288
No. of biscuits 1 packet contains = 12 biscuits
Total no. of biscuits = 3456
No. of cartons = 9
Then,
Cartons for 3456 biscuits = 9
Cartons for 1 biscuit = 9/3456
Cartons for 1920 biscuits = (9/3456) × 1920
= 5
Answer. 5 cartons are needed.
Hope it helps !!!
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