Math, asked by hemantkumar36961, 1 year ago

288 packets of biscuits, each having 12 biscuits, are packed in 9 cartons. How many such cartons are required to pack 1920 biscuits?​

Answers

Answered by jhanvigarg
18

Answer:

no. of packets = 288

no. of biscuits in 1 packet =12

so, no. of biscuits in 288 packets = 288 * 12 = 3456

Given that ,

3456 biscuits are packed in 9 cartoons

so , no. of biscuits in one cartoon = 3456/9

= 384

so , no of cartoonsrequired to pack 1920 biscuits are

1920/ 384

= 5

so, 5 cartoons are required to pack 1920 biscuits.

Hope it helps

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Answered by ritika2465
6

Answer:

5

Step-by-step explanation:

288 packets are packed in 9 cartons

therefore 288÷9=32

32 packets are there in each cartons

now,no. of biscuits=1920

no of packets=1920÷12=160

now no of cartons =160÷32=5

therefore no of cartons required is 5.

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