Math, asked by Manbs, 8 months ago

28a²b^3c - 12abc
+24ab²c^2. Factorise

Answers

Answered by radeshg04

2

Answer:

$4abc(7ab^{2}+6bc-3)$

Step-by-step explanation:

$28a^{2} b^{3} c- 12abc + 24ab^{2} c^{2}$

Take $4abc$ common,

$4abc(7ab^{2}+6bc-3)$

Here You go!!!

Mark as brainliest please.

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