Question

28th Question please answer fast friends........

Answer 1

1/sinθ - sinθ = a^3 
(1 - sin²θ)/sinθ = a^3 
cos²θ / sinθ = a^3 

similarly 
sin²θ / cosθ = b^3 

then 
a^4 b^2 + a^2 b^4 
= [cos²θ/sinθ]^(4/3) [sin²θ / cosθ]^(2/3) + [cos²θ/sinθ]^(2/3) [sin²θ / cosθ]^(4/3) 

= (cosθ)^(8/3) / (cosθ)^(2/3) + (sinθ)^(8/3) / (sinθ)^(2/3) 

= cos²θ + sin²θ 
= 1 

hope it helped u

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