Math, asked by aparrnarj, 1 year ago

28th question please solve this

Attachments:

Answers

Answered by sehnaya
0

let the naming of the cone, so it will be easier for you to understand,

so let the naming of big cone be A,B andC. same way let the naming of the small cone be A,P,Q. let the centre be O for the small cone. let the centre of big cone be M.

Ans: let the radius and height be r and h for smaller cone. similarly for bigger cone R respectively.

since , triangle AOQ~ triangle AMC ,

AO/AM= OQ/MC

h/30=r/R

r=hR/30 eq-1

since given volume of the smaller circle =1/27 (vol of larger cone)

1/3pie r square h=1/27 (1/3 pie R square × 30)

pie/3 (h×R/30)square h= 1/27 ×1/3 pie R square × 30

h cube= 30×30×30/27

Ans: h cube = 1000

h= 10 cm3.

Hope it helps , if yes plz mark as brainlest...

Thankyou

Answered by Anonymous
1

let the naming of the cone, so it will be easier for you to understand,

so let the naming of big cone be A,B andC. same way let the naming of the small cone be A,P,Q. let the centre be O for the small cone. let the centre of big cone be M.

Ans: let the radius and height be r and h for smaller cone. similarly for bigger cone R respectively.

since , triangle AOQ~ triangle AMC ,

AO/AM= OQ/MC

h/30=r/R

r=hR/30 eq-1

since given volume of the smaller circle =1/27 (vol of larger cone)

1/3pie r square h=1/27 (1/3 pie R square × 30)

pie/3 (h×R/30)square h= 1/27 ×1/3 pie R square × 30

h cube= 30×30×30/27

Ans: h cube = 1000

h= 10 cm3

Similar questions