Question

28th term from the end of the AP 3 ,8 ,13,...., 298. will be
answe​

Answer 1

an = a+ (n-1) d

298 = 3 + ( n-1 ) 5

298-3 = (n-1)5

295 = (n-1) 5

(n-1) = 295÷5

(n-1) = 59

n = 60 ( we get the no. of terms of the given AP )

28th term = a28

a28 = a+ (n-1) d

a28 = 3 + (28 -1)5

a28 = 3 + 135

a28 = 138

(the 28th term is 138)