Question

[29-(-2) {6-(7-3) }]÷[3×[5+(-3) ×(2) }]​

Answer 1

Answer:

$elloh$

$brainlist \: pls$

Step-by-step explanation:

 let's simplify it 

[29-(-2){6-4}]÷[3x{5+6}]

[29-(-2)x2] ÷[3x11]  =  [ 29- (-4)]÷33  = 33÷33 =  1

 

 so here is your ans. , friend , it is 1

Answer 2

We use BODMAS to solve the problem.

∴ [29 - (- 2) {6 - (7 - 3)}] ÷ [3 × {5 + (- 3) × (2)}]

= [29 + 2 {6 - 4}] ÷ [3 × {5 - 3 × 2}]

= [29 + 2 (2)] ÷ [3 × {5 - 6}]

= [29 + 4] ÷ [3 × {- 1}]

= 33 ÷ (- 3)

= - 11