Question

[29-(-2) {6-(7-3) }]÷[3×[5+(-3) ×(2) }]​

Answer 1

Answer:

$elloh$

Step-by-step explanation:

 let's simplify it 

[29-(-2){6-4}]÷[3x{5+6}]

[29-(-2)x2] ÷[3x11]  =  [ 29- (-4)]÷33  = 33÷33 =  1

 

 so here is your ans. , friend , it is 1

Answer 2

Answer:

[29+2{6-4}]/[3{5-3}2]

[29+4]/12

33/12

Step-by-step explanation: