. [29–(-2) {6—(7-3)}] ÷ [3× {5+(-3)×(2)}]
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ANSWER IS 1
STEP BY STEP EXPLANATION
[29-(-2){6-(7-3)}]÷[3×{5+(-3)×(-2)}
= [29-(-2){6-(7-3)}]÷[3×{5+6}
= [29-(-2){6-(7-3)}]÷[3×11}
= [29-(-2){6-(7-3)}]÷[33}
= [29+2 {6-(7-3)}]÷[33}
= [29+2 {6-4}]÷[33}
= [29+2 {2}]÷[33}
= [29+4]÷[33}
= [33]÷[33}
=1
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