Question

. [29–(-2) {6—(7-3)}] ÷ [3× {5+(-3)×(2)}]​

Answer 1

ANSWER IS 1

STEP BY STEP EXPLANATION

[29-(-2){6-(7-3)}]÷[3×{5+(-3)×(-2)}

= [29-(-2){6-(7-3)}]÷[3×{5+6}

= [29-(-2){6-(7-3)}]÷[3×11}

= [29-(-2){6-(7-3)}]÷[33}

= [29+2 {6-(7-3)}]÷[33}

= [29+2 {6-4}]÷[33}

= [29+2 {2}]÷[33}

= [29+4]÷[33}

= [33]÷[33}

=1