Question

[29-(-2){6-(7-3)}]÷×3×{5+(-3)×(-2)}]

Answer 1

ANS]

$(29 - ( - 2)(6 - (7 - 3))) \div 3 \\ \times (5 + ( - 3) \times ( - 2))$

$\frac{(29 - ( - 2)(6 - (7 - 3)))}{(3 \times(5 + ( - 3) \times ( - 2))) }$

$\frac{(29 - ( - 2)(6 - (4)))}{(3 \times (5 + ( - 3) \times ( - 2))}$

$\frac{(29 - ( - 2) \times (2))}{(3 \times (5 + 6))}$

$\frac{(29 - ( - 4))}{(3 \times (11))}$

$\frac{(29 + 4)}{(33)}$

$\frac{33}{33}$

$= 1$