Question

[29-(2)(6-(7-3))]÷[3×(5+(-3)×(-2))]​

Answer 1

$\frac{[29-(2)(6-(7-3))]}{[3 \times (5 + ( - 3) \times ( - 2))]} \\ \\ = \frac{29 - 2(6 - 4)}{3 \times (5 + ( - 6))} \\ \\ = \frac{29 - (2 \times 2)}{3 \times(5 - 6) } \\ \\ = \frac{29 - 4}{3 \times - 1} \\ \\ = \frac{25}{-3} \\ \\ = \frac{ - 25}{3} = - 8. \overline{3}$