[29–(-2){6–(7–3)}]÷[3×{5+(-3)×(-2)}]
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[29–(-2){6–(7–3)}] ÷ [3×{5+(-3)×(-2)}]
= [29+2{6–4}] ÷ [3×{5+6}]
= [29+2×2] ÷ [3×11]
= 33 ÷ 33
= 1
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