Question

29.25 g of NaCl is present in 529.25 g of the solution. find out the molality​

Answer 1

Answer:

molality=1 molal

Explanation:

mass of NaCl given = 29.25 g

mass of solution given = 529.25g

molality=number of moles of solute/kg of solvent

Number of moles of NaCl = given mass of NaCl/molar mass of NaCl

$= 29.25 g \div 58.44g \: per \: mol = 0.5moles$

$mass \: of \: solvent = 529.25 - 29.25 \\ = 500g = 0.5kg$

molality

$= 0.5mol \div 0.5k = 1m$

hence the molality of the solution is one.

Answer 2

Answer:

dear here is your answer

Explanation:

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