Question

29. A ball is projected horizontally from the top of
a tower with a velocity V. It will be moving at
an angle of 60° with the horizontal after time​

Answer 1

Answer:

Vx0 = V      initial X component of velocity

Vy0 = 0        initial Y componejnt of velocity

Vx = V          X component of velocity at time t

Vy = 1/2 g t^2     Y component of velocity at time t

Vy / Vx = tan 60 = 1.732

1.732 = 1/2 g t^2 / V

t = (3.46 V / g)^1/2