29. A ball is projected horizontally from the top of
a tower with a velocity V. It will be moving at
an angle of 60° with the horizontal after time
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Answer:
Vx0 = V initial X component of velocity
Vy0 = 0 initial Y componejnt of velocity
Vx = V X component of velocity at time t
Vy = 1/2 g t^2 Y component of velocity at time t
Vy / Vx = tan 60 = 1.732
1.732 = 1/2 g t^2 / V
t = (3.46 V / g)^1/2
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