Question

29. (a)
For the combination of resistors shown in the following figure, find
the equivalent resistance between M & N.
-M
1
R3​

Answer 1

Answer:

resistance between=(R3R4/R3+R4)+R1+R2

Answer 2

The equivalent resistance between M and N is $R_1+R_2+\dfrac{R_3R_4}{R_3+R_4}$

Explanation:

In the attached figure, it shows the combination of resistors $R_1,R_2,R_3\ and\ R_4$. Here, $R_3\ and\ R_4$ are in parallel. Let their equivalent is given by the formula as :

$\dfrac{1}{R}=\dfrac{1}{R_3}+\dfrac{1}{R_4}\\\\R=\dfrac{R_3R_4}{R_3+R_4}$............(1)

Now, resistors $R_1,R_2\ and\ R$ are in series. Their equivalent resistance is given by the formula :

$R_{eq}=R_1+R_2+\dfrac{R_3R_4}{R_3+R_4}$

So, the equivalent resistance between M and N is $R_1+R_2+\dfrac{R_3R_4}{R_3+R_4}$. Hence, this is the required solution.

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