Question

29.
A force of 6.0 N acts on a body of mass 1.5 kg for 2.0 S. Assuming the body to be mually al
rest, find :
(a) its velocity when the force stops acting,
(b) the distance covered in 5 s after the force starts acting.​

Answer 1

F= Ma

6N = 1.5a

a = 4 m/s2

The car is at rest so u =0 and V= 8 m/s

40 m

Answer 2

Force = 6 N

Mass = 1.5 kg

Time = 2 s

a) When we use the formula

$F = \frac{m( v - u)}{t}$

6 = $\frac{1.5 v}{2}$ ( as initial velocity (u) is 0 )

12 = 1.5 v

v = 12 ÷ 1.5

v = 8 m/s

b) d  = s × t

    d = 8 × 5

     d = 40 m

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