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A is three times as old as B today and A was four times as old as, B three years ago. Then what is
the sum of there present ages? 3A - 3 - 3 - 4 AB
TA) 12
BT 36
(C) 10
(D) 22
FL!.. civ vehicles are parked in a parking lot in a single row. After the first car, there is one
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we'll see how the weather is nice we can get the ball rolling on this one but I don't think I can make it work but I will be in touch soon to be xdukkdd you can come by to
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Step-by-step explanation:
Let the age of A be x and the age of B be y
x = 3 y ....(eqn 1)
Three years ago, their ages were x - 3 , y - 3 respectively
4 ( y - 3 ) = x - 3
Substitute x = 3 y (eqn 1)
4 y - 12 = 3 y - 3
y = 9
x = 3 y = 27
x + y = 36
Therefore the sum of their present ages is 36
Hope it Helps
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