Question

29
A is three times as old as B today and A was four times as old as, B three years ago. Then what is
the sum of there present ages? 3A - 3 - 3 - 4 AB
TA) 12
BT 36
(C) 10
(D) 22
FL!.. civ vehicles are parked in a parking lot in a single row. After the first car, there is one​

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

Let the age of A be x  and the age of B be y

x = 3 y   ....(eqn 1)

Three years ago, their ages were x - 3 , y - 3 respectively

4 ( y - 3 ) = x - 3

Substitute x = 3 y (eqn 1)

4 y - 12 = 3 y - 3

y = 9

x = 3 y = 27

x + y = 36

Therefore the sum of their present ages is 36

Hope it Helps