29. A metallic cylinder of radius 2 cm and height
6 cm is made of metal A. To reduce its weight,
a conical hole is drilled in the cylinder as
shown and is completely filled with lighter
metal B. The radius of the conical hole is
1.5 cm and its depth is 4 cm. Calculate the ratio
of the volume of the metal A to the volume of
metal B in the solid.
Answers
Answered by
0
Step-by-step explanation:
Volume of metal B=
3
1
πr
1
2
h
1
=
3
1
π(
2
3
)
2
(
9
8
)=
3
2π
Volume of metal A=πr
2
h−
3
1
πr
1
2
h
1
=
3
π
(3r
2
h−r
1
2
h
1
)
=
7×3
22
(3×9×5−
4
9
×89)=
21
22
(135−2)=
21
22×133
=139.33 cm
3
ratio =
2π
139.33×3
=
3.14
209
=
π
209
=
22
209×7
=
2
133
Answered by
1
Answer:
Step-by-step explanation:
Volume of metal B=
3
1
πr
1
2
h
1
=
3
1
π(
2
3
)
2
(
9
8
)=
3
2π
Volume of metal A=πr
2
h−
3
1
πr
1
2
h
1
=
3
π
(3r
2
h−r
1
2
h
1
)
=
7×3
22
(3×9×5−
4
9
×89)=
21
22
(135−2)=
21
22×133
=139.33 cm
3
ratio =
2π
139.33×3
=
3.14
209
=
π
209
=
22
209×7
=
2
133
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