Question

29. A reduction of 10% in the price of an article
enables a dealer to purchase 25 articles more for
45,000. What is the original price of the articles
(b) 150
(a) 100
(c) 200
(d) 250​

Answer 1

Answer:

Let original price=x

10% Of x= x* 10/100

= X/10

Reduction of 10% = X-X/10

=10x-x/10

=9x/10

no.of products bought initially=Y

before reduction In price=> XY=4500

after reduction =9x/10(Y+25)=4500

=9xy/10+225x/10=4500

9*4500+225x/10=4500(by taking lcm)

40500+225x=4500*10

40500+225x=45000

225x=45000-40500

225x= 4500

X= 4500/225

X= 900/45

X= 20

original cost of the article is Rs20.

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