29. A train travelling at 20 m s-accelerates at 0.5 m s-2 for 30 s. How far will it travel in this time?
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Answer: 825 m
Explanation:
Given:-
u(initial velocity)= 20 m/s
a(acceleration)= 0.5 m s-2
t(time taken)= 30 s
To find:-
s(distance travelled)
Solution:-
since, s=ut+1/2at^2
s= 20*30+1/2*0.5*(30)^2
s= 600+900/4
s=600+225
therefore, s=825 m
Answer- The distance travelled is 825 m.
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