Question

29. a3 (b-c)3 + b3(c-a)3 +c3 (a−b)3

Answer 1

Answer:

Let x = a(b - c)

y = b(c - a)

z = c(a - b)

So x + y + z = ab - ac + bc - ba + ca - cb

x + y + z = 0

therefore,

${x}^{3} + {y}^{3} + {z}^{3} = 3xyz \\ {(a(b + c))}^{3} + {(b(c + a))}^{3} + {(c(a + b))}^{3} = 3a(b - c)b(c - a)c(a - b)$

Answer 2

Answer:

this is correct................