Question

29. All surfaces shown in the figure are frictionless.
block of mass 2 kg is kept on a wedge of mas
10 kg. If the mass m remains stationary w.rt. wedge
the magnitude of force Pis (g = 10 m/s2)
(2kg)
10 kg
B = 3700
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Answer 1

Required Froce    $F = 90N$  

Explanation:

Let the acceleration of system is a

$Force = Mass \times Acceleration$    

$P = (M+m)a$

       $P = 12a$

F.B.D of block w.r.t wedge is (go through attached image)

  Balancing the force

$ma\sin(90 - 37) = mg\sin 37$  

$a = g\tan 37$

$a = 10\times\frac{3}{4}$

$a =7.5 \frac{m}{s^{2}}$

$F=12\times7.5$

Required force $F = 90N$ .

Answer 2

Answer:

P = 90N

Step-by-step explanation:

Please refer to the attachment below