29. Charge on the condenser in the
circuit shown in figure will be
(20170]
12 V
952
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302
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6μF
(A)18uc
(C)6uC
(B) 12uc
(D) 36uC
Answers
18uc
R1+R2=Req
Req=12
according to ohms law
V=IR
12=I X 12
I = 1 Amp
potential differences in R2(3 ohm)=V1
V1= IR2
V1= 1 X 3
V1= 3 Volt
Charge on condencer(q)=CV
C=6uf
q =CV¹
q = 6 X 3
q = 18uc
Answer:
18uc
Explanation:
Step : 1 R1+R2=Req Req=12
according to ohms law
V=IR
12=I X 12
I = 1 Amp
potential differences in R2(3 ohm)=V1
V1= IR2
V1= 1 X 3
V1= 3 Volt
Charge on condencer(q)=CV
C=6uf
q =CV¹
q = 6 X 3
q = 18uc
Step : 2 A moving electric charge creates a magnetic field, and an electric charge is related with an electric field. The electromagnetic field is made up of both electric and magnetic fields. The electromagnetic force, the cornerstone of physics, is produced by the interaction of the charges.
Step : 3 Test = k | Q | r 2 when E = F q. Test = k | Q | r 2 when E = F q. The size of the electric field produced by a point charge Q is determined by this equation. The distance r in the denominator is the separation between the point of interest and the point charge, Q, or the centre of a spherical charge. Three guidelines to keep in mind when dealing with charges: Positive charges push away one another. Repulsion between negative charges. Charges that are in opposition to one another attract.
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