Question

29. Draw the graphs of the following equations: 2x – 3y + 6= 0 2x + 3y – 18 = 0 y – 2 = 0 Find the vertices of the triangle so obtained. Also, find the area of the triangle
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Answer 1

Answer:

2x – 3y + 6= 0 2x + 3y – 18 = 0 y – 2 = 0

Step-by-step explanation:

Answer 2

Answer:

Given,

2x−3y+6=0

2x−3y=−6

Divide the equation by −6

⇒−3x+2y=1

2x+3y−18=0

2x+3y=18

Divide the equation by 18

⇒9x+6y=1

y−2=0

⇒y=2

Vertices of trianlge formed by  the intersection of these lines is given by:

a(3,4),b(0,2),c(6,2)

area of trianlge

A=2ax(by−cy)+bx(cy−ay)+cx(ay−by)

=23(2−2)+0(2−4)+6(4−2)

=26×2

=6

Step-by-step explanation:

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