Question

29. Find the roots of quadratic equation
$3x - 13 = \frac{30}{x}$
by the method of factorisation.​

Answer 1

Answer:

$3x - 13 = \frac{30}{x}$

$x(3x - 13) = 30$

$3{x}^{2} - 13x - 30 = 0$

$3 {x}^{2} - (18 - 5)x - 30 = 0$

$3 {x}^{2} - 18x + 5 x- 30 = 0$

$3x(x - 6) + 5(x - 6) = 0$

$(3x + 5)(x - 6) = 0$

$either$

$(3x + 5) = 0$

$3x = - 5$

$x = \frac{ - 5}{3}$

$or$

$(x - 6 )= 0$

$x= 6$

therefore, the factors of the given equation are -5/3 and 6.