Question

29. Find three different solutions of the equation 2x-4y=8.​

Answer 1

Answer:

1. If we put x = 0, then y = - 2
2. If we put x = 1, then y = - 2/3
3. If we put x = 2 then y = - 1

Step by step explanation:

Given:

• Equation - 2x - 4y = 8

To Find:

• Three different solutions.

Now, for finding different solution of a equation we have to assume a value of 'x' and put into equation. By putting we obtain value of 'y'.

Case 1). Let x = 0

=> 2x - 4y = 8

=> 2(0) - 4y = 8

=> 0 - 4y = 8

=> y = -2.

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Case 2). Let x = 1

=> 2x - 4y = 8

=> 2(1) - 4y = 8

=> 2 - 4y = 8

=> - 4y = 6

=> y = - 4/6

=> y = - 2/3

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Case 3). Let x = 2

=> 2x - 4y = 8

=> 2(2) - 4y = 8

=> 4 - 4y = 8

=> - 4y = 4

=> y = - 1.

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Hence, Solution of given equation are:

1. If we put x = 0, then y = -2
2. If we put x = 1, then y = -2/3
3. If we put x = 2, then y = -1.