Question

29 grams of water at 9°C is heated until its temperature is 25°C. If the specific heat of water is 4.18 J/g°C, calculate the amount of heat energy needed to cause this rise in temperature.

Answer 1

Answer:

Calculate specific heat as c = Q / (mΔT) . In our example, it will be equal to c = -63,000 J / (5 kg * -3 K) = 4,200 J/(kg·K) . This is the typical heat capacity of water.Oct 27, 2020

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