Question

29. If Ā= 21 +43 + 6k is parallel to 3 = xi +12) + 18k then
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Answer 1

We know angle between two vectors is given by,

cosθ=∣A∣∣B∣A

.B

--------------(A)

∣A∣=62+62+32=9

∣B∣=72+42+42=9

And A

.B

=(6i^+6j^−3k^).(7i^+4j^+4k^)=42+24−12=54

Now putting the above values in A we get,

θ=cos−18154

θ=sin−11−322

θ=sin−135

Answer 2

Answer:

1) 1000+2000×60000+100000