29. If A and B are the zeros of the polynomial 6x2+x-2, find the value of A2-B2
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Answer:
6x^2+x-2
6x^2+(4-3)x-2
6x^2+4x-3x-2
2x(3x+2)-1(3x+2)
(2x-1)(3x+2)=0
2x-1=0 3x+2=0
x=1/2 and x=-2/3
so A =1/2 , B = -2/3
A^2-B^2=(A+B)(A-B)
(1/2-2/3)(1/2+2/3)
(1/6)(5/6)
ans = 5/36
Step-by-step explanation:
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