Question

29
If a bike is travelling with velocity 10m/s and its uniform
acceleration is 4m/s2. Then velocity acquired by the bike
in 10seconds is​

Answer 1

Given :-

• Initial velocity, u = 10 m/s
• Acceleration, a = 4 m/s²
• Time taken, t = 10 seconds

To find :-

• Final velocity of the bike, v

According to the question,

➞ v = u + at [First equation of motion]

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

➞ Substituting the values,

➞ v = 10 + 4 × 10

➞ v = 10 + 40

➞ v = 50

• So, the final velocity acquired by the bike is 50 m/s.

___________________

More formulas :

Newton's first equation of motion :

• v = u + at

Newton's second equation of motion :

• s = ut + ½ at²

Newton's third equation of motion :

• v² = u² + 2as

Answer 2

Answer:

Given :-

• Initial velocity (U) = 10 m/s
• Acceleration (A) = 4 m/s
• Time taken (T) = 10 sec

To Find :-

Final velocity

Solution :-

Here we will use newton first Equation of motion

$\huge \rm{v = u + at}$

Here,

V = Final Velocity

U = Initial velocity

A = Acceleration

T = Time taken

$\tt \implies \: v = 10 + 4 \times 10$

$\tt \implies \: v = 10 + 40$

$\tt \implies \: v = 50 \: mps$

Hence :-

Final velocity of bike is 50 m/s.