Math, asked by amansoni31041, 9 months ago

29. If M, and M2 are the feet of the perpendiculars from the S1 and S2 of the ellipse x²/9 + y²/16 = 1 on the tangent at a point P on the ellipse, then (S, M)(S2 M2) is equal to :
(a) 16
(b) 9
(c) 4
(d) 3

Answers

Answered by sanjamrajpal
0

Answer:

Step-by-step explanation:

answer is 3 for sure

Answered by silentlover45
4

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=>. (S, M)(S2 M2) = 9

The product of perpendicular from the foci on any tangent to the ellipse x²/a² + y²/1b² = 1 is equal to b².

We know that the product of perpendicular from two foci S1 and S2 of the ellipse x²/9 + y²/16 = 1, on the tangent at a point P on the ellipse is equal to the square of the semi minor axis.

(S, M)(S2 M2) = 9

silentlover45.❤️

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