29. If M, and M2 are the feet of the perpendiculars from the S1 and S2 of the ellipse x²/9 + y²/16 = 1 on the tangent at a point P on the ellipse, then (S, M)(S2 M2) is equal to :
(a) 16
(b) 9
(c) 4
(d) 3
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Answer:
Step-by-step explanation:
answer is 3 for sure
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=>. (S, M)(S2 M2) = 9
The product of perpendicular from the foci on any tangent to the ellipse x²/a² + y²/1b² = 1 is equal to b².
We know that the product of perpendicular from two foci S1 and S2 of the ellipse x²/9 + y²/16 = 1, on the tangent at a point P on the ellipse is equal to the square of the semi minor axis.
(S, M)(S2 M2) = 9
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