29. If o<h<q then lim(q" +h")= =
1 e 2 h 3 9 4 0
n
>00
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Answer:
(3)
Step-by-step explanation:
since h < q ; h/q < 1
( q" +h") ^1/n
= (q^n)^1/n [1+(h/q)^n) ^1/n ]
now if n → ∞ ; 1/n → 0 and hence...
Lt ( q" +h") ^1/n
= q ( 1 + 0 )^0
= q × 1
= q
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