29. If P(-9a-2, -b) divides the line segment joining A
(3a+1, -3) & B (80,5) in the who 3:1 find the values
of a & b.
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Answer:We have,
ABAP=31= AP+PBAP=31→ 3AP=AP+BP
→ 2AP=BP
BPAP=21
So, P divides AB in the ratio 1:2.
:Coordinates of Pure(1+21x5+2x2,1+21x-8+2x1)
=(3,2)
Since,P(3,2) lies on the line 2x-y+k=0.
.:2*3-2+k=0 → k=-4
TYPE III ON DETERMINATION OF THE TYPE OF A GIVEN QUADRILATERAL
Step-by-step explanation:
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