Question

29. If the sum of two numbers is 79 and
their difference is 23, then find the
numbers.
30.24 is divided into two parts such
that 7 times the first part added to
5 times the second part makes 146.
Find the first part.




please answer the question ​

Answer 1

Answer:

29. 79-23= 56

Therefore the answer is 23+56= 79

30. 2nd part=146

Therefore, 1st part= 146-24= 122

Ans= 122

Verification= 146-122= 24

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Answer 2

Question (1) :

If the sum of two numbers is 79 and their difference is 23 , then find the numbers.

Answer:

Let the greater number be x and the smaller number be y.

From First condition,

x+y=79................... (1)

From Second condition,

x-y=23............. (2)

Adding (1) and (2) we get,

2x= 102

x=102/2

x=51

Substituting the value of x in (1) we get,

51+y=79

y=79-51

y=28

Therefore, The greater number is 51 and the smaller number is 28.

Question (2) :

24 is divided into the two parts such that 7 times the first part added to 5 times the second part makes 146.Find the first part.

Answer:

It is give that 24 is divided into two parts.

Let the first part be x and the second part be y.

From the first condition,

x+y=24.............. (1)

From second condition,

7x+5y=146............(2)

Multiplying equation (1) by 5 we get,

5x+5y=120...........(3)

Subtracting equation (3) from (2) we get,

2x=26

x=26/2

x=13

Substituting the value of x in equation (1) we get,

13+y=24

y=24-13

y=11

So the first part is 13 and the second part is 11.

So