29. Ifmoment of a force F passing through a point with position vector r about origin is given by rx É. Then find the
moment about point whose co-ordinate is (1, 2, 3) of a force represented by 2i +2j+2k acting at the point (-
2,3,1).
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Answer:
A force F=2i+j−k acts at a point A whose position vector is 2i−j. Find the moment of F about the origin If the point of application of F moves from the point A to the point B (position vector 2i+j), find the work done by F.
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ANSWER
r
ˉ
=2i−j
F
ˉ
=2i+j−k
Hence moment of force about origin is
=
F
ˉ
×
r
ˉ
=(2i+j−k)×(2i−j)
=−i−2j−4k
And the work done
=
F
ˉ
.(r
2
−r
1
)
=(2i+j−k).(2i+j−(2i−j))
=(2i+j−k).(2j)
=2 joules
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