Question

29. In the figure, DE II BC. If AD = x, DB = -2. AE = x + 2 and EC = х - 1. then the value of xis С x -1 E х+2 А В Dx-2 х​

Answer 1

Answer:

In Δ ABC, DE ∥ BC

∴

DB

AD

=

EC

AE

(By basic proportionality theorem)

⇒

x−2

x

=

x−1

x+2

⇒x(x−1)=(x+2)(x−2)

⇒x

2

−x=x

2

−4

⇒x=4.

Answer 2

Step-by-step explanation:

in∆ABC,DE||BC

therefore

DB

AD=EC AE

(by basic proportionality thorem)

=x-2

x=x-1

x+2

==x(x-1)=

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