Question

29.
In the given circle with centre O and diameter 10 cm,
PQ = 6 cm and RS = 8 cm. Find the length of UV
if OU L PQ, OV I RS and U-O-V.
a. 10 cm
b. 7 cm
c. 5 cm
d. 6 cm​

Answer 1

Answer:

7cm

Step-by-step explanation:

Given, diameter = 10cm.

=> Radius = 5cm

Construction : Join OP, OR.

Here, in ∆OPU,

OP = 5cm (Radius)

PU = 3cm (perpendicular from center bisects chord)

=> By Pythagoras theorem, UO = 4cm.

Similarly, in ∆OVR

VR = 4cm

OR = 5cm

=> By Pythagoras Theorem, OV = 3cm

Adding UO + OV

=> UV = 3cm + 4cm

=> UV = 7cm