Question

29. In the given figure, ABC is a triangle right-angled at A, with AB = 21 cm and
AC = 42 cm. With the vertices A, B and C as centres, arcs are drawn each of
radius 10 cm, find the area of the shaded region. (Use 1 = 3.14)​

Answer 1

: Required Answer

➝ Given

ABC is a triangle right-angled at A, with AB = 21 cm and AC = 42 cm.

➝ find

it's saded region

➝ Solution

The side of triangle 21 cm and 42 cm

The area of triangle is

$\frac{1}{2} \times 42 \times 21 = 441 \: cm {}^{2}$

➝ the sector of corner have some radius 10 cm

➝ Therefore , the total area is combines sector of equal angles

➝ The Angle in triangle sum up to give 180°

➝ therefore, the total area of sector =$\frac{180}{360} \times \pi10 {}^{2} = 50 \times 3.14cm {}^{2} = 157cm {}^{2}$

➝ The Area of shaded region is given = $441 - 157 = 284 \: cm {}^{2}$