Question

29. merchant has 120 litres of oil of one kind, 180 litres of another kind and 240 litres of a third
kind he wants to sell the oil by filling the three kinds of oil in tins of equal capacity What
should be the greatest capacity of such a tim?

please answer with steps
answer if only sure
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Answer 1

Answer:

We need to find the HCF or GCD that is Greatest Common Divisor

120=2

3

×3×5

180=2

2

×3

2

×5

240=2

4

×3×5

GCD=2

2

×3×5=60

The greatest capacity = 60 liters

So the merchant needs to fill 60 liters of all types of oils

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