Question

29 no please help me

Answer 1

Solution :
________

Given that :

$y = \frac{ {e}^{ x} + {e}^{ - x} }{ {e}^{x} - {e}^{ - x} }$

On differentiate with respect to x :
$\frac{dy}{dx} = \frac{ ({e}^{x} - {e}^{ - x})( {e}^{x} - {e}^{ - x}) - ( {e}^{x} + {e}^{ - x} )( {e}^{x} + {e}^{ - x} ) }{ { ({e}^{x} - {e}^{ - x}) }^{2} } \\ \\ = > \frac{dy}{dx} = \frac{ {( {e}^{x} - {e}^{ - x} ) }^{2} - {( {e}^{x} + {e}^{ - x}) }^{2} }{ {( {e}^{x} - {e}^{ - x}) }^{2} }$