29. Pjove that: sec 0 + tan 0-1
tan - sec 0 +1
1+ sin
cos 0
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2
Answer:
According to given sum,
sin (1+tan)+cos (1+cot)=sec+cosec
=> LHS= sin (1+tan)+cos (1+1/tan)
=> sin (1+tan)+cos (1+tan)/tan
=> (1+tan)(sin+cos/tan)
=> (1+tan)(sin.tan+cos)/tan
=> (1+tan)(sin^2/cos+cos)/tan
=> (1+tan)(sin^2+cos^2)/tan.cos
=>(1+tan)/tan.cos
=>(1/tan.cos)+tan/tan.cos
=>( cot/cos)+(1/cos)
=> cosec +sec
LHS= RHS.
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Answered by
2
According to given sum,
sin (1+tan)+cos (1+cot)=sec+cosec
=> LHS= sin (1+tan)+cos (1+1/tan)
=> sin (1+tan)+cos (1+tan)/tan
=> (1+tan)(sin+cos/tan)
=> (1+tan)(sin.tan+cos)/tan
=> (1+tan)(sin^2/cos+cos)/tan
=> (1+tan)(sin^2+cos^2)/tan.cos
=>(1+tan)/tan.cos
=>(1/tan.cos)+tan/tan.cos
=>( cot/cos)+(1/cos)
=> cosec +sec
LHS= RHS.
Like my answer if you find it useful!
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