Question

29) Prove that angles opposite to equal sides of an isosceles triangle are equal.
30) Prove that the line segment joining the midpoints of two sides of a triangle is parallel to the
third side and half of it.
31) Prove that the angle subtended by an arc at the centre is double the angle subtended by it at
any point on the remaining part of the circle.
ale ABC in which BC= 7cm, B= 75° and AB + AC=13 cm.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

29.

Step-by-step explanation:

Let △ABC be an isosceles triangle such that AB =AC Then we have to prove that ∠B=∠C Draw the bisector AD of ∠A meeting BC in D

Now in triangles ABD and ACD We have AB=AC (Given)

∠BAD=∠CAD (because AD is bisector of ∠A

AD=AD (Common side)

Therefore by SAS congruence condition we have

△ABC≅△ACD

⇒∠B=∠C

(Corresponding parts of congruent triangles are equal )