Question

29. Sides of a triangular field are 15 m, 16 m and 17 m. With the three corners of two field a cow, a buffalo
field which cannot be grazed by the three animals.
and a horse are tied separately with ropes of length 7 m each to graze in the field. Find the area of the​

Answer 1

Explanation:

Given radius of each sector=7m

Now area of sector with ∠C=

360

∠C

×πr

2

=

360

∠c

×π(7

2

)m

2

Area of the sector with ∠B=

360

∠B

×πr

2

=

360

∠B

×π(7

2

)m

2

And area of the sector with ∠H=

360

∠H

×πr

2

=

360

∠H

×π(7

2

)m

2

Therefore sum of the areas =

360

∠C+∠B+∠H

×π×49=77m

2

Semiperimeter=24 m

Therefore area of the triangular field =

s(s−a)(s−b)(s−c)

=24

21

m

2

So area which can not be grazed =(24

21

−77)m

2

Answer 2

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above answer is right

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