Math, asked by avinabghosh, 2 months ago

29. Simplify
(i) 1-71 - 181 + 1-51 - 2
(iii) 2032 + (-16)
(ii) 13 - 61 + 18 - 101 - 112 - 81
(iv) (-1)17 x (-1)8​

Answers

Answered by borhadeprathamesh911
0

Answer:

GIVEN

Shobo's mother age is 6 times of Shobo.

After 5yrs Shobo's age will be 1/3 of his mothers present age.

TO FIND :- Their present ages

SOLUTION

Let Shobo's Present age be x

Then Shobo's mother age will be 6x

NOW,

According to the Question,

x + 5 = 1/3 ( 6x )

We will solve this linear equation in two Variable to get the ages of Shobo and his mother.

x + 5 = 1/3 (6x)

=> x + 5 = 1/3 × 6x

=> x + 5 = 2x

=> x - 2x = -5

=> -x = -5

=> x = 5

Hence Shobo's present age is 5yrs and present age of mother will be

Hence Shobo's present age is 5yrs and present age of mother will be 5 × 6 = 30yrs.

VERIFICATION

x + 5 = 1/3 (6x)

=> 5 + 5 = 1/3 × 6 × 5

=> 10 = 2 × 5

=> 10 = 10

LHS = RHS

Our answer is Correct !

Answered by ranjana1980sri
5

Answer:

1. 57

2. 2016

3. -158

4. 119

MARK ME AS BRILLIANT

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