Question

29. The 10th term of the arithmetic progression 4,7,10
is
a) 21
b) 27
c) 31
d)33​

Answer 1

Answer:

AP:4,7,10,....

a = first term = 4

d = common difference= 7-4 = 3

now,

$a+(n-1)d=a_{n} \\4+(10-1)3=a_{10}\\a_{10} = 4+ 27 = 31$

Answer 2

$\huge\mathfrak\green{\underline{\underline{Solution}}}$

$\huge{\underline {\tt{ Given\::-}}}$

$\tt{ A.P \:is\: 4\: ,7\: ,10\: }$

$\tt{ a = 4}$

$\tt{ d = a_2 - a_2 }$

$\tt{ d = 7 - 4 = 3 }$

${\red{\boxed{\tt{\green{d = 3}}}}}$

${\boxed{\tt{\pink{Formula : a_n = a + ( n-1)×d}}}}$

$\tt{ a_10 = 4 + ( 10 - 1 ) × 3 }$

$\tt{ a_10 = 4 + 9 × 3 }$

$\tt{ a_10 = 4 + 27 }$

$\tt{ a_10 = 31 }$

${\boxed{\tt{\blue{ 10th\: term\: is \:31 }}}}$

${\purple{\boxed{\tt{\orange{Option\: ( c )\: is\: correct.}}}}}$