Math, asked by krushnachnagul, 6 months ago

29
The average of 5 consecutive even numbers A,
B, C, D and Eis 5% of 840. What is product of
C and E?​

Answers

Answered by Shanaya2594
1

Step-by-step explanation:

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Answered by qwachieve
0

Given:

The five even numbers are A, B, C, D, and E.

The average of five consecutive even numbers is 5 percent of 840.

To find:

To evaluate the product of C and E.

Solution:

Let us take five consecutive even numbers A, B, C, D, and E as X, X+2, X+4, X+6, X+8, respectively.

Average of numbers = Sum of the numbers/ Total count of numbers (formula 1)

Since there are five even numbers

Therefore,

Total count of numbers = 5

Sum of numbers = (X+ X+2+ X+4+ X+6 +X+8)

= 5X + 20

Average of the five consecutive even numbers = 5% of 840

= (5/100) × 840

= 42

Putting the values in the formula 1,

42 = (5X + 20) / 5

5X + 20 = (42× 5)

5X = 210 – 20

5X = 190

X = 38

The five consecutive even numbers are X, X+2, X+4, X+6, and X+8.

The final values of A, B, C, D, E are 38, 40, 42, 44, and 46, respectively.

On multiplying C and E, we get,

42× 46 = 1932.

Hence, the product of C and E is 1932.

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