29
The average of 5 consecutive even numbers A,
B, C, D and Eis 5% of 840. What is product of
C and E?
Answers
Step-by-step explanation:
you can go on with this process ...but I must say that this is totally not the same question..but it will surely help you to overcome your problem
Given:
The five even numbers are A, B, C, D, and E.
The average of five consecutive even numbers is 5 percent of 840.
To find:
To evaluate the product of C and E.
Solution:
Let us take five consecutive even numbers A, B, C, D, and E as X, X+2, X+4, X+6, X+8, respectively.
Average of numbers = Sum of the numbers/ Total count of numbers (formula 1)
Since there are five even numbers
Therefore,
Total count of numbers = 5
Sum of numbers = (X+ X+2+ X+4+ X+6 +X+8)
= 5X + 20
Average of the five consecutive even numbers = 5% of 840
= (5/100) × 840
= 42
Putting the values in the formula 1,
42 = (5X + 20) / 5
5X + 20 = (42× 5)
5X = 210 – 20
5X = 190
X = 38
The five consecutive even numbers are X, X+2, X+4, X+6, and X+8.
The final values of A, B, C, D, E are 38, 40, 42, 44, and 46, respectively.
On multiplying C and E, we get,
42× 46 = 1932.
Hence, the product of C and E is 1932.