Question

29. The coefficients of static and dynamic
friction are 0.7 and 0.4. The minimum force
required to create motion is applied on a
body and if it is further continued, the
acceleration attained by the body in ms-2
is (g = 10m/s)
1) 7 24 33 4) Zero
ont of ototie friction between​

Answer 1

Answer:

let mass be m

then normal force(N)=mg=10m downwards

now force required to move=max. friction

static frictional force=coeff*N=0.7*10m=7m

As body starts moving dynamic friction act

so dynamic friction force=coeff*N=0.4*10m=4m

net force=applied force -frictional force

7m-4m=3m

F=m*a

3m=m*a

a=3m/s^2

hopefully it helps you

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