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the
Pythagorean triplet whose one
member is 63.
Answers
Answer:
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Answer:
Thus, the Pythagoras triplets having 63 as its member is 16, 63 and 65
Step-by-step explanation:
We know that,
Pythagoras triplets are of the form 2m, m² - 1,
m² + 1
Now,
one of these number must be 63
Let substitute and see,
Also, remember m can't be equal to a fraction or decimal. And it can't be a negative number as well.
2m = 63
m = 63/2
Now, that is not the value of m
m² - 1 = 63
m² = 63 + 1
m² = 64
m = √64
m = 8
Thus, m = 8
Now, we can find the other numbers.
2m = 2 × 8 = 16
m² - 1 = 63
m² + 1 = 8² + 1 = 64 + 1 = 65
Thus, the Pythagoras triplets having 63 as its member is 16, 63 and 65
We can check also,
16² + 63² = 65²
256 + 3969 = 4225
√4225 = 65
Thus, it is true
Hope it helped and you understood it........All the best