29. The shape of the top surface of a table is a trapezium. Find its area, if its
parallel sides are 1m and 1.2m and perpendicular distance between them is
0.8m.
Answers
Answer:
20.88
Step-by-step explanation:
Parallel sides=1m and 1.2m
height=0.8m
Area of table top==\frac{1}{2}\times\left(sum\ of\ parallel\ sides\right)\times\left(dis\tan ce\ between\ them\right)\ =
2
1
×(sum of parallel sides)×(distance between them)
=\frac{1}{2}\times\left(1+1.2\right)\ \left(0.8\right)=
2
1
×(1+1.2) (0.8)
=\frac{2.2\times0.8}{2}=
2
2.2×0.8
==\frac{2.2\times0.8}{222.2×0.8==\frac{2.2\times0.8}{2}= 2
2.2×0.8 = 0.88\ m^20.88 m
2
Step-by-step explanation:
Given :-
The shape of the top surface of a table is a trapezium.Its parallel sides are 1m and 1.2m and perpendicular distance between them is 0.8m.
To find:-
Find the area of the top surface of the table ?
Solution:-
Given that :
The shape of the top surface of a table is a trapezium.
Length of the two parallel sides of the trapezium
= 1 m and 1.2 m
Let a = 1 m and b = 1.2 m
The perpendicular distance between them
= 0.8 m
Let h = 0.8 m
We know that
Area of a Trapezium =
(1/2)perpendicular distance between Parallel sides×( Sum of the lengths of the two parallel sides) sq.units
=> Area of a Trapezium = (1/2)h(a+b) sq.units
On Substituting these values in the above formula
=> (1/2)(0.8)(1+1.2) sq.m
=> (0.8/2) (2.2) sq.m
=> (0.4)(2.2) sq.m
=> 0.88 sq.m
Answer:-
The Area of the top surface of the given table is 0.88 sq.m
Used formula:-
Area of a Trapezium:
(1/2)perpendicular distance between Parallel sides×( Sum of the lengths of the two parallel sides = (1/2)h(a+b) sq.units