29. The work done when a gas is compressed by an average pressure of 0.50 atm so as to
decrease its volume from 400 cm3 to 200cm
1) 10.13 J 2) 20.13J 3) 30.13 J4) 40.13 J
please give me the answer quickly.in step by step
step by step
Answers
Answered by
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Answer:
option c....
Explanation:
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Given :
- Pressure = 0.5 atm
- Initial volume = 400 cm ³
- Final volume = 200 cm³
To find :
- Work done
How to solve :
- Simply substitute the the given values in the formula inorder to find the unknown variable.
Solution :
Work done on the gas is given by ,
⇒ W = - P ΔV
⇒ W = - P ( V' - V )
Now let's substitute the given values in the above equation ,
⇒ W = - 0.5 ( 200 - 400 )
⇒ W = - 0.5 X - 200
⇒ W = 100 atm / cm³
⇒ W = 100 X 0.001 atm L
⇒ W = 0.1 atm L
Unit conversion
→ 1 atm L = 1.01325 × 10^5 Pa L
→ 1 atm L = 101325 N/m² × 10^-3 m^3
→ 1 atm L = 101.325 Nm
Hence ,
→ 1 atm L =101.325 J
So ,
⇒ W = 0.1 x 101.325 J
⇒ W = 10.1325 J
Hence ,
The work done is 10.13 J .
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